Dependence of spontaneity on temperature :
For a process to be spontaneous, at constant temperature and pressure, there must be decrease in free energy of the system in the direction of the process, i.e. Δ G P, T < 0. Δ G P, T = 0 implies the equilibrium condition and Δ G P, T > 0 corresponds to non-spontaneity.
Gibbs-Helmholtz equation relates the free energy change to the enthalpy and entropy changes of the process as :
= Δ H – T Δ S ...
Text Solution
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(i) Δ G = Δ H – T Δ S
If T Δ S dominates Δ H at high temperature then Δ G < 0 hence CaCO 3 decomposes at high temperature.
(ii) Δ G = Δ H – T Δ S = 2.1 × 10 3 – 20 × 298 < 0.
(iii) Reaction to be spontaneous
Δ G < 0 ⇒ Δ H – T Δ S < 0 ⇒ Δ T >
⇒ T >
⇒ T > 2000 K.
(iv) Clearly at 400 K, reaction is in equilibrium
Δ G = 0
Δ S =
= –
= – 100 cal K –1
(v) Use Δ G = Δ H – T Δ S
Δ G = – 15 –
= – 12.84 Kcal mol –1
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